0: o=suffix 1: cn=Manager,o=suffix 2: ou=people,o=suffix 3: uid=kdz,ou=people,o=suffix 4: cn=addresses,uid=kdz,ou=people,o=suffix 5: uid=hyc,ou=people,o=suffixThen:
dn.base="ou=people,o=suffix" match 2; dn.one="ou=people,o=suffix" match 3, and 5; dn.subtree="ou=people,o=suffix" match 2, 3, 4, and 5; and dn.children="ou=people,o=suffix" match 3, 4, and 5.
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